First of all we have to arrange the data in ascending order as shown below:
28, 40, 43, 43, 45, 50, 50
Total number of values = 7
Since the number of values is odd, the median will be the middle value i.e. 4th value which is 43. Median divides the data in two halves:
1st Half = 28, 40, 43
2nd Half = 45, 50, 50
Q1 or the First Quartile is the middle value of the lower or 1st half which is 40.
Q3 or the Third Quartile is the middle value of the upper or second half, which is 50.
IQR or the Inter Quartile Range is the difference of Q3 and Q1.
So, IQR= Q3 – Q1 = 50 – 40 = 10
Thus, IQR for the given data is 10
Answer:
384, 216, 290, 192, 384
1446, 1 roll
Step-by-step explanation:
For rectangular boxes, calculate the sum of each side, then multiply it by two.
Box 1: 2(18 x 5) + 2(18 x 4) + 2(5 x 4) = 364
Box 3: 2(11 x 8) + 2(8 x 3) + 2(3 x 11) = 290
Box 5 is a cube (all sides equal), so you can find 1 side's area and multiply it by 6.
Box 5: 6(8 x 8) = 384
For triangular boxes, calculate the edges, then find the triangular area using area = 0.5(base x height).
Box 2: (15 x 3) + (9 x 3) + (12 x 3) + 2(0.5)(9 x 12) = 216
Box 4: 2(13 x 2) + (10 x 2) + 2(0.5)(10 x 12) = 192
Total: 364 + 290 + 384 + 216 + 192 = 1446
Rolls of wrapping paper:
Area of 1 roll = 30 x 60 = 1800
Since 1446 is less than 1800, you only need 1 roll of wrapping paper.
The greatest difference you can get is 42
The range of the integer is given as:
Smallest = -16
Largest = 26
So, the range is calculated as:
Range = Largest - Smallest
Substitute known values
Range = 26 - (-16)
Evaluate the difference
Range = 42
Hence, the greatest difference you can get is 42
Read more about range at:
https://brainly.in/question/6887467
Answer:
Step-by-step explanation:
-a + 6b = -3 + 6 * (-6) = -3 - 36 = -39
