Puting it into the quadrait equation ((-b+-[b^2-4ac]^(1/2)/2a), we get that x= 31^(1/2)-5 or 31^(1/2)+5
<span>Y(−3, 4) is the original
</span><span>(x, y) → (x − 2, y + 1) is the rule you're using
(-3, 4) </span>→ (-3 - 2, 4 + 1)
(-3, 4) → (-5, 5)
<span>Y'(–5, 5)</span>
Answer:
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Step-by-step explanation:
<span>f(x)=-6x-1
</span><span> X Y
0 -1
-1 5
6 -37
5 -31</span>
