Answer:
14.284
Explanation:
Know parameters from the problem are: the amount of the substance/ gas molecule is 1.20 mol, the Temperature of the gas is 17 Celsius degrees (i.e. 290.15 K [17 Celsius degrees plus 273.15 K]), the pressure exerted on the container by the gas is 2.0 atm.
The unknown ( what you are asked to find) is the volume that the gas would occupy in its container under those conditions above; V=?.
We use the ideal gas equation here; PV=nRT. R in this equation is called the molar gas constant or Ideal has constant. There are many values for R given different circumstances. For the condition of this problem, R's value is 0.08205 L atm/mol K.
Make V the mathematical subject of the equation PV=nRT.
V=(nRT)/P
V=(1.20 mol x 0.08205 L atm per mol per K x 290.15 K)/ 2.0 arm
V= (28.568169 L atm mol per mol per K)/ 2.0 atm
V= 14.284 [(L atm mol K)/(atm mol K) atm mol K is in the numerator and the denominator would be canceled. Leaving only L.
Therefore, V= 14.284 L of N
