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aleksandrvk [35]
3 years ago
9

∠A=angle, A, equals

Mathematics
2 answers:
pogonyaev3 years ago
7 0

Answer:

∠A=angle, A, equals

^\circ

∘

degrees

Round your answer to the nearest hundredth.

∠A=angle, A, equals

^\circ

∘

degrees

Round your answer to the nearest hundredth.

∠A=angle, A, equals

^\circ

∘

degrees

Round your answer to the nearest hundredth.

∠A=angle, A, equals

^\circ

∘

degrees

Round your answer to the nearest hundredth.

∠A=angle, A, equals

^\circ

∘

degrees

Round your answer to the nearest hundredth.

∠A=angle, A, equals

^\circ

∘

degrees

Round your answer to the nearest hundredth.

∠A=angle, A, equals

^\circ

∘

degrees

Round your answer to the nearest hundredth.

∠A=angle, A, equals

^\circ

∘

degrees

Round your answer to the nearest hundredth.

Step-by-step explanation:

andre [41]3 years ago
5 0

Answer:

What are you asking?

Step-by-step explanation:

∠A=angle, A, equals  ^\circ  ∘ degrees  Round your answer to the nearest hundredth. \

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Long Division: (3x^4-8x^3-x^2+9x+5) / (x-2) pleaseee answer this
Drupady [299]

3<em>x</em>⁴ = 3<em>x</em>³ • <em>x</em>, and

3<em>x</em>³ (<em>x</em> - 2) = 3<em>x</em>⁴ - 6<em>x</em>³

Subtract this from the numerator to get a remainder of

(3<em>x</em>⁴ - 8<em>x</em>³ - <em>x</em>² + 9<em>x</em> + 5) - (3<em>x</em>⁴ - 6<em>x</em>³) = -2<em>x</em>³ - <em>x</em>² + 9<em>x</em> + 5

-2<em>x</em>³ = -2<em>x</em>² • <em>x</em>, and

-2<em>x</em>² (<em>x</em> - 2) = -2<em>x</em>³ + 4<em>x</em>²

Subtract this from the previous remainder to get a new remainder of

(-2<em>x</em>³ - <em>x</em>² + 9<em>x</em> + 5) - (-2<em>x</em>³ + 4<em>x</em>²) = -5<em>x</em>² + 9<em>x</em> + 5

-5<em>x</em>² = -5<em>x</em> • <em>x</em>, and

-5<em>x</em> (<em>x</em> - 2) = -5<em>x</em>² + 10<em>x</em>

Subtract this from the last remainder to get a new one of

(-5<em>x</em>² + 9<em>x</em> + 5) - (-5<em>x</em>² + 10<em>x</em>) = -<em>x</em> + 5

-<em>x</em> = -1 • <em>x</em>, and

-1 (<em>x</em> - 2) = -<em>x</em> + 2

This gives a new remainder of

(-<em>x</em> + 5) - (-<em>x</em> + 2) = 3

3 does not divide <em>x</em>, so we're done.

So, we have

(3<em>x</em>⁴ - 8<em>x</em>³ - <em>x</em>² + 9<em>x</em> + 5) / (<em>x</em> - 2) = 3<em>x</em>³ - 2<em>x</em>² - 5<em>x</em> - 1 + 3/(<em>x</em> - 2)

7 0
4 years ago
A map uses a scale of 3/4 in = 80 miles. If two buildings are 60 miles apart in real life, how far apart would they be drawn on
Alla [95]

Given:

The scale of a map is \dfrac{3}{4}\ in=80\ miles.

The distance between two buildings is 60 miles.

To find:

The distance between the given building on the map.

Solution:

We have,

\dfrac{3}{4}\ in=80\ miles

It means, 80 miles in real life = \dfrac{3}{4}\ in on the map.

1 mile in real life = \dfrac{3}{4\times 80}\ in on the map.

60 mile in real life = \dfrac{3\times 60}{4\times 80}\ in on the map.

                              = \dfrac{180}{320}\ in on the map.

                              = \dfrac{9}{16}\ in on the map.

Therefore, the buildings are \dfrac{9}{16}\ in apart on the map.

7 0
3 years ago
.<br> The angle measures of a triangle are shown in the diagram.<br> What is the value of x?
vodka [1.7K]

Answer:

ok the second one the answer is 66

Step-by-step explanation:

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6 0
4 years ago
A toxic radioactive substance with a density of 7 milligrams per square centimeter is detected in the ventilating ducts of a nuc
uysha [10]
For this case we have an equation of the form:
 y = A * (b) ^ t
 Where,
 A: initial amount
 b: decrease rate
 t: time in years.
 Substituting values we have:
 7 = A * (0.5) ^ ((1/20) * t)
 For t = 45 years we have:
 7 = A * (0.5) ^ ((1/20) * 45) 
 Clearing A:
 A = 7 / ((0.5) ^ ((1/20) * 45))
 A = 33.3
 Answer:
 
the density of the substance when it was deposited 45 years ago was:
 
A = 33.3 milligrams per square centimeter
5 0
4 years ago
Which ratio is equivalent to 4/16 A. 2:4•• B. 6 to 20 C. 8:32 D. 12 to 64 Write the ratio as a unit rate. 286 miles in 5 1/2 hou
NeX [460]
1) Which ratio is equivalent to [tex] \frac{4}{16} [tex]?
[tex] \frac{4}{16} * 2 = \frac{8}{32} [tex], or 8:32.

2) Write the ratio as a unit rate [tex] ( \frac{286miles}{5 \frac{1}{2} hours} ) [tex]
Set the equation up like this:
[tex] \frac{286miles}{5 \frac{1}{2} hours} = \frac{Xmiles}{1 hour}\\
286*1=(5 \frac{1}{2})*x\\
286 = \frac{11x}{2}\\
11x= 572 [tex]
x = 52 [tex] \frac{miles}{hour} [tex]

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6 0
3 years ago
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