Answer:
a. y^ -1 = e^x +2
Step-by-step explanation:
y = ln (x-2)
Exchange x and y
x = ln (y-2)
Solve for y
Raise each side with a base of e
e^ x = e^(ln(y-2)
e^x = y-2
Add 2 to each side
e^x +2 =y
The answer is a.0.32 km.
The speed that a tsunami can travel is modeled by the equation is s = 356√d.
It is given:
s = 200 km/h
d = ?
Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562
Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32
Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>
Answer c venue hiddenwords was your gonna night you want
Answer:
ANY line that has a slope of 3, and any y intercept other than -5.
Step-by-step explanation:
Parallel lines have the same slopes, but different y intercepts.
So, it would be ANY line that has a slope of 3, and any y intercept other than -5.
here are a few examples:
y=3x-17
y=3x+4
y=3x+3293248032843209.3432492384032984032984023840398249082
y=3x+5
y=3x-1
y=3x
Answer:
-30
Step-by-step explanation:
10 x 3 = 30
10 x -3= -30
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two negatives makes a positive
two positives markets a negative
and
a positive and a negative makes a negative