First, lets create a equation for our situation. Let

be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>

<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:

. So lets replace the values in our formula to find the average of our function:
![\frac{25(10)+100-[25(2)+100]}{10-2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%2810%29%2B100-%5B25%282%29%2B100%5D%7D%7B10-2%7D%20)



We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
Answer:
A. 2x+4y=20 B. x+6y=10 C. 3x+3y=13 D. 4x+2y=20
A= 3,2
B= -1,-1
C= 3,4
D= 1,4
Answer: 18450
Step-by-step explanation:
Answer:

Step-by-step explanation:
The lion population in a certain reserve drops by 5\%5%5, percent every year. Currently, the population's size is 200200200.
Write a function that gives the lion population size,
Each year, the population drops to 95% of its previous value. (100 - 5)%
That is, the population is multiplied by 0.95 each year.
Repeated multiplication is signified by an exponent.
Here, that exponent is the number of years from today (t).
<h3>There fore, The population function can be written as ...</h3><h3 /><h3> P(t) = 200·0.95^t</h3><h3>

</h3>