Answer:
The whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square is 6 ft
Step-by-step explanation:
Here we are required find the size of the sides of a dunk tank (cube with open top) such that the surface area is ≤ 160 ft²
For maximum volume, the side length, s of the cube must all be equal ;
Therefore area of one side = s²
Number of sides in a cube with top open = 5 sides
Area of surface = 5 × s² = 180
Therefore s² = 180/5 = 36
s² = 36
s = √36 = 6 ft
Therefore, the whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square = 6 ft.
9/3 =3
(X+7)^2/ (x+7) = x+7
1/x-1
3(x+7)/x-1
3x+21/x-1
The answer is Answer 30 i think
Answer:
Below.
Step-by-step explanation:
y + 2 > -3(x + 1)
y + 2 > -3x - 3
y > -3x - 5
The graph will be the graph of the line y = -3x - 5 (dotted line), with the area above the line shaded.
