Answer:
Therefore, Point M( 1 , -2 ) is the Mid point of segment ST.
Step-by-step explanation:
Given:
Let,
point S( x₁ , y₁) ≡ ( -1 , 1)
point T( x₂ , y₂) ≡ (3 , -5)
Point M( x , y ) is the Mid point of segment ST.
To Find:
Point M( x , y )= ?
Solution:
As Point M( x , y ) is the Mid point of segment ST.
So we have Mid Point Formula as
On substituting the given values in above equation we get
Therefore, Point M( 1 , -2 ) is the Mid point of segment ST.
The coordinate A(-1, 1) reflected over y-axis is (1, 1) is the coordinate of E, hence the two figures are congruent
- The given figures are quadrilaterals, in order to determine whether they are similar, we need to check if they are reflections of each other.
- For the Quadrilateral ABCD, the coordinate of A is at A(-1, 1) and for the Quadrilateral DEFG, the coordinate of E is at E(1, 1).
- Note that if an object is reflected over the y-axis the transformation is (x, y)->(-x, y)
- We need to check whether if we reflect the coordinate A over the y-axis we will get coordinate E
Since the coordinate A(-1, 1) reflected over y-axis is (1, 1) is the coordinate of E, hence the two figures are congruent
Learn more on reflections here:brainly.com/question/1908648
There are 4.29 cases in the units
<h3>How to determine the number of cases?</h3>
The given parameters are:
Units = 60
Rate = 14 units per case
The number of cases is then calculated as:
Case = Unit/Rate
This gives
Case = 60/14
Evaluate
Case = 4.29
Hence, there are 4.29 cases in the units
Read more about unit rates at:
brainly.com/question/19493296
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