assalam o aalaikum
Step-by-step explanation:
1. At the Blue Jays game, Steven Matz (height = 1.2m) throws a baseball(140g) straight in
the air with 95N of force for 30cm.
1. What is the speed of the ball 2.4 m above the ground?
2. What is the maximum height of the ball (assuming no air resistance)?
This is a freefall problem with an acceleration of -10m/s (a poor approximation of g :P)
a=g
v=gt+v0
h=gt^2/2+v0t+h0 where v0 is initial velocity and h0 is initial height.
You have:
h=-5t^2+10t+3
Since h0=3, the springboard is 3 meters above the water.
...
The diver hits the water when h=0.
5t^2-10t-3=0
Using the quadratic equation for simplicity:
t=(10±√160)/10
t=(10±4√10)/10 seconds, since t>0
t≈2.26 seconds (to nearest hundredth of a second)
So the diver hits the water about 2.26 seconds after (s)he leaves the springboard.
Answer:
No.
Step-by-step explanation:
This is incorrect because a straight line or a straight angle must consist of two right angles, one obtuse angle, and one acute angle. If you have two up two singles than the sum of their measures will be greater than 1 80 so you can't get it straight.
