Answer:
The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of
.
Step-by-step explanation:
The formula from the maximum distance of a projectile with initial height h=0, is:

Where
is the initial velocity.
In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is
. The critical points of the function are those who make
:


The critical value inside the interval is
.

The second step is to find the values of the function at the endpoints of the interval:

The biggest value of f is gived by
, therefore
is the absolute maximum.
In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of
.
Answer:
The domain of the function is [-9,7] and the range of the function is [-6,4]
Answer: 8 hours
<u>Step-by-step explanation:</u>
Company 1: 3.25x + 26
Company 2: 3.50x + 24
3.50x + 24 = 3.25x + 26
0.25x +24 = 26 <em>subtracted 3.25x from both sides</em>
0.25x = 2 <em>subtracted 24 from both sides</em>
x = 8 <em>divided both sides by 0.25</em>
<u>Check:</u>
Company 1: 3.25x + 26 = 3.25(8) + 26 = $52
Company 2: 3.50x + 24 = 3.50(8) + 24 = $52