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2 years ago

12

If θ is an angle in standard position and its terminal side passes through the point (21,-20), find the exact value of \cot\thet

acotθ in simplest radical form.

1 answer:

STatiana [176]2 years ago

3 0

Buying the president of the state national national

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Determine the amplitude or period as requested. Period of y = - 1/3 * sin 2x

Sedbober [7]

Answer:

$Period = \pi$

Step-by-step explanation:

Given

$y = -\frac{1}{3} * \sin(2x)$

Required

The period

A sine function is represented as:

$y =A \sin(Bx + C) + D$

Where

$Period = \frac{2\pi}{B}$

By comparing:

$y =A \sin(Bx + C) + D$ and $y = -\frac{1}{3} * \sin(2x)$

$B = 2$

So, we have:

$Period = \frac{2\pi}{2}$

$Period = \pi$

Hence, the period of the function is $\pi$

3 0

2 years ago

Hanna's dad is designing a new rectangular garden for his backyard. He has a 20ft fence to put around the garden. He wants the l

vovangra [49]

Answer:

<em>3 3/4 feet</em>

Step-by-step explanation:

Given

Perimeter of the garden = 20ft

If he wants the length of the garden to be 2 1/2 longer than its width, then;

L = 2 1/2 + W

L is the length

W is the width

Perimeter of the garden = 2(L+W)

P20 = 2(5/2 + W+W)

20 = 5 + 2W+2W

20 - 5 = 4W

15 = 4W

W = 15/4

<em>W = 3 3/4 ft</em>

<em>Hence the width of the garden is 3 3/4 feet</em>

7 0

2 years ago

What's a slop in math

Setler79 [48]

Answer:

Its the division of x axis divided by y axis

4 0

2 years ago

Read 2 more answers

G(r)=−1−7r<br> i know this much<br> g(6) but what does that equal?

VladimirAG [237]

The answer to this question is -8r

7 0

2 years ago

Solve 2x2 + 4x = 30 using the Quadratic Formula.

Maslowich

Answer:

$x=-5, 3$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

<u>Algebra I</u>

Standard Form: ax² + bx + c = 0
Quadratic Formula: $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Step-by-step explanation:

<u>Step 1: Define equation</u>

2x² + 4x = 30

<u>Step 2: Rewrite into Standard Form</u>

2x² + 4x - 30 = 0

<u>Step 3: Define variables</u>

a = 2

b = 4

c = -30

<u>Step 4: Solve for </u><em><u>x</u></em>

Substitute: $x=\frac{-4\pm\sqrt{4^2-4(2)(-30)} }{2(2)}$
Evaluate: $x=\frac{-4\pm\sqrt{16-4(2)(-30)} }{2(2)}$
Multiply: $x=\frac{-4\pm\sqrt{16+240} }4}$
Add: $x=\frac{-4\pm\sqrt{256} }4}$
Evaluate: $x=\frac{-4\pm16 }4}$
Factor: $x=\frac{4(-1\pm4)}4}$
Divide: $x=(-1\pm4)$
Add/Subtract: $x=-5, 3$

And we have our final answer!

6 0

2 years ago