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3 years ago

Just wondering does anyway else do vava? 8th grade

Mathematics

2 answers:

dangina [55]3 years ago

4 0

Answer:

I have heard of it but I myself do not

Dimas [21]3 years ago

3 0

Answer:

What's vava just wondering also your in 8th grade?

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1 markers cost $7.04 Which equation would help determine the cost of 7 markers!

Elena-2011 [213]

The answer to the question is A

3 0

3 years ago

What is the simplest form of the expression 6x(x − 4) − 16x2 − (9x − 1)

BigorU [14]

If the term in the middle is 16x^2

6x^2-24x-16x^2-9x+1 =

-10x^2-33x+1

5 0

3 years ago

Sarah is a computer engineer and manager and works for a software company. She receives a

daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = $a$

Given that:

$a_4=129\\a_{10}=207$

Formula for $n^{th}$ term of an Arithmetic Progression is given as:

$a_n=a+(n-1)d$

Where $d$ will represent the number of projects increased every year.

and $n$ is the year number.

$a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)$

Subtracting (2) from (1):

$78 = 6d\\\Rightarrow d =13$

By equation (1):

$129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90$

Number of projects in the first year = 90

b)

Number of projects in the twelfth year =

$a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233$

Each project pays $500

Earnings in the twelfth year = 233 $\times$ 500 = $116500

Sum of an AP is given as:

$S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938$

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 $\times$ 1938 = $969000

8 0

3 years ago

Sally bought some candy bars for $1.25 each and some sodas for $1.49 each. If she bought a total of 38 items and spent $50.38 ho

hammer [34]

Answer:

26 candy bars and 12 sodas

Step-by-step explanation:

This problem can be solved by a simple system of equations

I am going to call x the number of candy bars that Sally bought and y the number of sodas that Sally bought.

The fact that she bought 38 itens means the x + y = 38.

She spent $50.38. The value she spent is the sum of the number of candy bars multplied by the value of the candy bar and the number of sodas multiplied by value of a soda. So 1.25x + 1.49y = 50.38

So we have to solve the following system:

1)x + y = 38

2)1.25x + 1.49y = 50.38

From 1), we have that x = 38 - y. I am going to replace it in 2)

1.25(38-y) + 1.49y = 50.38

-1.25y + 1.49y = 50.38 - 47.5

0.24y = 2.88

y = 12.

Sally bought 12 sodas.

In 1: x = 38-y = 38-12 = 26

Sally bourght 26 candy bars

6 0

3 years ago

Read 2 more answers

If a function is derivable at a point it is also continous at that point explain why?

Artyom0805 [142]

For a function to have a derivative in a point has to be continuous at the point, that is, it has to be defined at that point, other wise the derivative would be meaningless.

5 0

3 years ago