
The positive integer is 6.
The consecutive integers are 6 and 7.
Answer:(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)
Step-by-step explanation:
We can rewrite left side into right side form
(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)
we can expand it
(x^2+y^2)^2=x^4+x^2y^2+x^2y^2+y^4
(x^2+y^2)^2=x^4+y^4+2x^2y^2
we can add and subtract 2x^2y^2
(x^2+y^2)^2=x^4+y^4+2x^2y^2+2x^2y^2-2x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+2x^2y^2+2x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+4x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+(2xy)^2
(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2
Answer:
The common difference is
or 0.2
Step-by-step explanation:
Given:
Arithmetic Sequence -2, -1 4/5, -1 3/5, -1 2/5,
First term = a₁ = -2
Second term = a₂ = 
Third term = a₃ = 
Fourth term = a₄ = 
To Find:
Common Difference = d = ?
Solution:
Formula for Common Difference d ,

∴ 
The common difference is
or 0.2
It's 6/35 because of means multiply and take numerator times numerator and denominator times denominator when you multiply fractions. 2 x 3 = 6 over 5 x 7 = 35. 6/35.
Answer:
A
when you simplify the equation you get A