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dalvyx [7]
3 years ago
13

What is the measure of AU

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
6 0

Answer:

Step-by-step explanation:

Given: The measure of the arc QU=88°, ∠QUA=111°.

To find: The measure of the arc AU.

Construction: Join QX and UX and AX, where X is the center of the circle such that ∠UXA=x.

Solution: It is given that  The measure of the arc QU=88°, ∠QUA=111°.

Now, we know that The measure of a minor arc is the same as the measure of the central angle that corresponds to it, therefore

If the minor arc QU=88°, then ∠QXU=88°.

Also, we know that the major central angle is double of the inscribed angle, thus

∠QXA=2(∠QUA)

⇒∠QXA=2(111°)

⇒∠QXA=222°

Using the angle sum property for a point X, we have

∠QXA+∠QXA=360°

⇒222°+88+x=360°

⇒310°+x=360°

⇒x=50°.

Again, The measure of a minor arc is the same as the measure of the central angle that corresponds to it, thus

The measure of the arc AU is same as ∠UXA that is 50°,therefore, the measure of AU is 50°.

Hence, option B is correct.

ASHA 777 [7]3 years ago
4 0
It is 50 degrees just took the test
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What is the average rate of change of f(x) = -x2 + 3x + 6 over the interval –3
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Answer:

\frac{\Delta y}{\Delta x}  =\frac{f(x_2)-f(x_1)}{x_2-x_1} =\frac{6-(-12)}{3-(-3)} =\frac{18}{6}= 3

Step-by-step explanation:

To find the average rate of change of a function over a given interval, basically you need to find the slope. The mathematical definition of the slope is very similar to the one we use every day. In mathematics, the slope is the relationship between the vertical and horizontal changes between two points on a surface or a line. In this sense, the slope can be found using the following expression:

Average\hspace{3}rate\hspace{3}of\hspace{3}change=Slope=\frac{y_2-y_1}{x_2-x_1}  =\frac{f(x_2)-f(x_1)}{x_2-x_1}

So, the average rate of change of:

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Over the interval -3

Is:

f(x_2)=f(3)=-(3)^2+3(3)+6=-9+9+6=6\\\\f(x_1)=f(-3)=-(-3)^2+3(-3)+6=-9-9+6=-12

\frac{\Delta y}{\Delta x}  =\frac{f(x_2)-f(x_1)}{x_2-x_1} =\frac{6-(-12)}{3-(-3)} =\frac{18}{6}= 3

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<h3>How to describe transformations, graph, and state domain & range using any notation?</h3>

The function is given as:

f(x) = -2|x + 6|

The above function is an absolute value function, and an absolute value function is represented as:

f(x) = a|x - h| + k

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So, the domain is the set of all real numbers

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Hence, the descriptions of the transformations are:

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Read more about absolute value function at

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