Alright.
For 7, you'll want to put congruent sides equal to each other, assuming they are parallelograms. So, you'll get the two equations:
3x+2=23
2y-7=9
Solve using GEMDAS/PEMDAS, and you'll get these answers.
3x+2=23
3x=21
x=7
2y-7=9
2y=2
y=1
For 8, you'll want to do the exact same thing, formatting the numbers to equal each other. You'll get these two equations:
3y+5=14
2x-5=17
Solving them would make:
3y+5=14
3y=9
y=3
2x-5=17
2x=22
x=11
For 9, you have to remember that the angle opposite of one angle in a defined parallelogram are congruent. Thus:
130=2h
5k=50
solve them and you get
h=65
k=10
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Hope that helped. Good luck.
An addition sign between 978 and 842 would make the equation true!
1.875 ounces for each student
Answer:
3x²+6x+2
Step-by-step explanation:
f(x)+g(x)-h(x)
=(3x+5)+(4x²-2)-(x²-3x+1)
=3x+5+4x²-2-x²+3x-1
=6x²+2+3x
=3x²+6x+2 (rearrange)
