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Nitella [24]
3 years ago
8

Henry went to an amusement park with $150.00 and spent all of it. He spent 1/5 of the money on parking He spent $37.00 on admiss

ion to the park He spent 40% of the money on food He paid a $10 fee for admission into a waterpark located inside the amusement park He spent the remainder of his money on games that cost $1.50 each How many games did Henry play?
Mathematics
1 answer:
sashaice [31]3 years ago
7 0

Answer:

8 games

Step-by-step explanation:

According to the problem, calculation of the given data are as follows,

Total amount = $150

Spent on Parking = 1/5 or 20% = $150 × 20% = $30

Spent on admission = $37

Spent on food = 40% = $150 × 40% = $60

Spent on admission in waterpark = $10

Each game cost = $1.5

So, let number of games played be X, then

$30 + $37 + $60 + $10 + $1.5X = $150

$137 + $1.5X = $150

1.5X = $150 - $137

1.5X = $13

X = $13 ÷ 1.5 = 8.67 or 8 games

Hence, Henry can play 8 games.

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4 is added to one fifth of w
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M is the midpoint of CB, CM = 3x+1, and MB = 5x−9.<br>Determine the value of x.
MrRissso [65]

Answer:

x = 5

Step-by-step explanation:

Since both sides are given, set both sides equal to eachother.

3x + 1 = 5x - 9

Segment CM is on the left and segment MB is on the right. From now on, solve for x.

Step 1: Isolate x by itself by subtracting the lesser value

3x + 1 = 5x - 9

-3x        -3x                     the x's on the left cross out

---------------------

 1 = 2x - 9

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----------------

10 = 2x

__________________________________________________________

Step 2: Divide each side by 2 to get rid of x's coefficient

10 = 2x

/2     /2

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5 = x

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__________________________________________________________

Solving for CB: Substitute x for both sides since x = 5

3(5) + 1 = side CM

15 + 1 = side CM

16 = side CM

__________________________________________________________

Solving for CB: Solve for the other side (segment MB)

5(5) - 9 = side MB

25 - 9 = side MB

14 = side MB

__________________________________________________________

Solving for CB: Lastly, add up the sides

16 + 14 = segment CB

30 = segment CB

__________________________________________________________

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