P(H,H,H)=P(H,T,H)
This is classical probability, so the probability of an event is the number of "favorable" events over total events.
The total number of events, by the counting principle, is 2^3=8.
The total number of events remains the same for P(H,H,H) and P(H,T,H), as you're still flipping 3 coins with two sides.
For P(H,H,H) the favorable event is (H,H,H) so 1, for P(H,T,H) the favorable event is (H,T,H) also one.
Conclusion:
P(H,H,H)=P(H,T,H)=1/8
8 is:
a)2x+3
b)7x^2
c)3x^2+2x+1
d)x^2+2x+7
e)x^2+2x+3
f)7x^2+2x+1
g)3x
h)x^2+3x
9 is:
a)5x
b)4x+9
c)4x+2
d)4x-2
54/x = 6...multiply both sides by x
54 = 6x...divide both sides by 6
54/6 = x
9 = x
Answer:
Yes
Step-by-step explanation:
You got it
