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julia-pushkina [17]
3 years ago
7

Question -3+13x=9.

Mathematics
2 answers:
aalyn [17]3 years ago
5 0

Answer:

-3+13x=9.

13x=9+3

13x=12

x=12/13

i proved it by putting value of x in reactant side you get product .

-3+13×12/13=9

brilliants [131]3 years ago
5 0

Answer:

x = 12/13

Step-by-step explanation:

-3 + 13x = 9

Adding 3 to both sides,

13x = 12

Dividing both sides by 13,

x = 12/13

We can prove it by putting the value of x we got in the given equation:

LHS = -3 + 13x

       = -3 + 13 (12/13)

       = -3 + 12

       = 9 = RHS

Hence, proved.

Hope it helps :)

Please mark my answer as the brainliest

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Translate this sentence into a multi-step equation Six more than the quotient of a number and 8 is equal to 2.
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What does f(-1) =_<br> and x=_ ?
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Answer:

F(-1) = 1

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Step-by-step explanation:

1) Assume that f(-1) = y1

So that point A (x1 = -1; y1) is a point lying in the graph representing the equation y = f(x)

As it can be seen in the figure, the graph representing that equation crosses point (-1; 1)

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So that point B (x2; y2 = -2) is a point on the graphy representing the equation y = f(x)

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5 0
3 years ago
Find the average velocity of the function over the given interval.
snow_lady [41]

Answer:

Average velocity of the function over the given interval

              =  log(\frac{7}{4} ) -2

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given function y = 3/x -2 ...(i)

The average velocity of the function over the given interval

             Average velocity  = \frac{1}{b-a} \int\limits^b_a {(\frac{3}{x} -2)} \, dx

                               =    \frac{1}{7-4} \int\limits^7_4 {(\frac{3}{x} -2)} \, dx

now integrating

                           =   \frac{1}{3}( \int\limits^7_4 {(\frac{3}{x} )} \, dx-2\int\limits^7_4 {1} \, dx )

                           = \frac{1}{3} (3 (log x) - 2 x )_{4} ^{7}

                        =   \frac{1}{3}( (3 (log 7) - 14 )-(3 log 4 -8))

by using formulas

                 log a-log b = log(a/b)

  on simplification , we get                  

                 = \frac{1}{3}( (3 (log 7) -3 log 4 ) - \frac{1}{3} (6)

                = log(\frac{7}{4} ) -2

Average velocity of the function over the given interval

              =  log(\frac{7}{4} ) -2

 

 

6 0
3 years ago
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