Which expression is equivalent to the expression below
1 answer:
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Answer:
The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.
Step-by-step explanation:
let S be the sample space for the inspection of the light bulbs.
Therefore, n(s) = 800
let ' A ' be the event of no defects bulbs.
Therefore, n(A) = 796
Now the Experiment probability for a light bulb chosen has no defects will be given by,
Substituting the values we get
The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.