Can someone help me plz
1 answer:
You might be interested in
Given:
The largest circle has a radius of R=7 units.
Let x be the radius of the large shaded circle.
The small shaded circles have a radius of 1/5 of the large shaded circle.
=> the small shaded circles have a radius of r=x/5
By adding up radii, we have the equation
2(r+x+r)=2(x/5+x+x/5)=2R=2*7=14
Simplify:
7x/5=14/2
x=5
=> r=1
Area of outer circle =
Area of large shaded circle =
Area of 4 small shaded circles =
Total area of shaded circles =
Shaded area as a fraction of that of the outer circle
The largest circle has a radius of R=7 units.
Let x be the radius of the large shaded circle.
The small shaded circles have a radius of 1/5 of the large shaded circle.
=> the small shaded circles have a radius of r=x/5
By adding up radii, we have the equation
2(r+x+r)=2(x/5+x+x/5)=2R=2*7=14
Simplify:
7x/5=14/2
x=5
=> r=1
Area of outer circle =
Area of large shaded circle =
Area of 4 small shaded circles =
Total area of shaded circles =
Shaded area as a fraction of that of the outer circle
Answer:
The number of ways Tony and Maria can both be selected for the committee is 8 ways.
Step-by-step explanation:
i) Tony and Maria have to be on the committee together or not at all.
ii) Let us consider Tony and Maria as combined as one person.
Therefore now we can say that the number of eligible people for the committee = 9 - 1 = 8.
iii) therefore the number of ways that both Tony and Maria can be selected for the committee are
= 8C1 =