Which of the following is the radical expression of2 times d to the seven tenths power? (2 points)

A jewelry store marks up the price of bracelets they purchase at $30.00 each by 75%. What is the markup and new price of each br

horrorfan [7]

The new price is 52.50
30x2=60
30/4=7.5
7.5x3=22.5
22.50+30= 52.50

3 0

3 years ago

A line is a undefined term because

SashulF [63]

The best answer I can think of is that a line doesn't have a point where it starts or stops, but instead goes on forever, unlike a ray which has a start or end point but not the other, and a line segment which has a start and stop point. Hope this helps!

7 0

3 years ago

To find the height of a pole, a surveyor uses a theodolite. The theodolite is 4 ft tall. The surveyor stands 140 feet away from

Ad libitum [116K]

Tan 44° = x/140

x = 140 tan 44°

x approx = 140 * 0.9657 = 135.198

Remember, we need to add another 4 feet, so the answer would be 139.198 feet

6 0

3 years ago

Read 2 more answers

Rita started to run on a treadmill after setting its timer for 93 minutes. The display says that she has finished 24% of her run

Alexxx [7]

Answer

22

Step-by-step explanation:

24%=24/100, she finished 24% of her run and of means to multiply so 24/100 x93= 22.32. 22.32 rounded to the nearest tenth is 22 so 22 minutes is the amount of time that has gone by :)

8 0

2 years ago

On a snow day, Mason created two snowmen in his backyard. Snowman A was built to a height of 51 inches and Snowman B was built t

mr_godi [17]

Answer:

A ( t ) = -4t + 51

B ( t ) = -2t + 29

t < 11 hours ... [ 0 , 11 ]

Step-by-step explanation:

Given:-

- The height of snowman A, Ao = 51 in

- The height of snowman B, Bo = 29 in

Solution:-

- The day Mason made two snowmans ( A and B ) with their respective heights ( A(t) and B(t) ) will be considered as the initial value of the following ordinary differential equation.

- To construct two first order Linear ODEs we will consider the rate of change in heights of each snowman from the following day.

- The rate of change of snowman A's height ( A ) is:

$\frac{d h_a}{dt} = -4$

- The rate of change of snowman B's height ( B ) is:

$\frac{d h_b}{dt} = -2$

Where,

t: The time in hours from the start of melting process.

- We will separate the variables and integrate both of the ODEs as follows:

$\int {} \, dA= -4 * \int {} \, dt + c\\\\A ( t ) = -4t + c$

$\int {} \, dB= -2 * \int {} \, dt + c\\\\B ( t ) = -2t + c$

- Evaluate the constant of integration ( c ) for each solution to ODE using the initial values given: A ( 0 ) = Ao = 51 in and B ( 0 ) = Bo = 29 in:

$A ( 0 ) = -4(0) + c = 51\\\\c = 51$

$B ( 0 ) = -2(0) + c = 29\\\\c = 29$

- The solution to the differential equations are as follows:

A ( t ) = -4t + 51

B ( t ) = -2t + 29

- To determine the time domain over which the snowman A height A ( t ) is greater than snowman B height B ( t ). We will set up an inequality as follows:

A ( t ) > B ( t )

-4t + 51 > -2t + 29

2t < 22

t < 11 hours

- The time domain over which snowman A' height is greater than snowman B' height is given by the following notation:

Answer: [ 0 , 11 ]

8 0

3 years ago