3 years ago

The equation y= ax describes the graph of a line. If the value of a is negative,

Mathematics

1 answer:

Firdavs [7]3 years ago

4 0

Answer:

Goes up and to the left

Step-by-step explanation:

You might be interested in

Grant pays 10 cents per minute plus $5 per month for telephone long distance. Write an algebraic expression for m minutes of lon

dolphi86 [110]

The question is asking for the amount of minutes Grant can possibly use in a month. So to <span>algebraically express this, the equation, </span>0.10 m+5=$ sums it up.

5 0

4 years ago

Erin is making a dozen cupcakes and wants to put 3 chocolate kisses on top of each one. How many does she need?

QveST [7]

Answer:

C. 36

Step-by-step explanation:

3x12=36 :]

3 0

3 years ago

Solve (i) 4/15+x=17/30

Anna007 [38]

Answer:

3/10

Step-by-step explanation:

4/15+x=17/30

x=17/30-4/15

x=17/30-8/30

x=9/30

simplify

x=3/10

3 0

3 years ago

Condense the following logarithm: <br><img src="https://tex.z-dn.net/?f=5%20log_%7B4%7D%28a%29%20%20-%206%20log_%7B4%7D%28b%29%2

aleksley [76]

log 4 ( a^5 ) - log 4 ( b^6 ) =

log 4 ( a^5 / b^6 )

4 0

3 years ago

Joe began to increase the speed of his car at 2:00 P.M. Since that time,the speed of Joes car has been steadily increasing by 1

Olegator [25]

Answer:

7 mins

Step-by-step explanation:

Current speed of Joes Car = 65.5 mph

We have to find the time interval for which the car exceeded the speed limit of 55 mph.

While, we are given that the speed of the car was constantly increasing, hence the speed over all increased from the limit of 55 mph = 65.50-55.00 = 10.50 mph

We are also given that Joes car was increasing speed at a constant rate of 1.50 mph for every passing minute. Hence

1.50 mph is increased in 1 minute

1 mph will be increase in $\frac{1}{1.5}$ minutes

Hence

10.50 mph will be increased in $\frac{1}{1.5} \times 10.50$ minutes

$= \frac{10.5}{1.5}$

$=7$

Hence joes car was exceeding the limit of 55 mph for 7 minutes.

8 0

3 years ago