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andreev551 [17]
3 years ago
10

Plz help

Mathematics
1 answer:
tankabanditka [31]3 years ago
5 0

Answer:

B.

Because if it is converted to percentages it would be easier to see.

-225%, -250%, -275%.

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In the triangle below,<br> y = [ ? ] cm. Round to the<br> nearest tenth.
sattari [20]

Answer:

The answer is

<h2>12.3 cm</h2>

Step-by-step explanation:

Since the triangle is a right angled triangle we can use trigonometric ratios to find y

To find y we use cosine

cos∅ = adjacent / hypotenuse

From the question

y is the adjacent

The hypotenuse is 15

So we have

\cos(35)  =  \frac{y}{15}  \\ y = 15 \cos( 35 )  \\ y = 12.28728

We have the final answer as

<h3>12.3 cm to the nearest tenth</h3>

Hope this helps you

7 0
3 years ago
12. The width of a rectangle is 16.55 inches. The length of the rectangle is half its width.
zepelin [54]
The answer is D

16.55 divide by 2= 8.275
8.275+8.275+16.55+16.55=49.65
4 0
3 years ago
Find two positive consecutive integers such that the square of the first added to three times the second is 24
Naddika [18.5K]

Answer:

3 and 5

Step-by-step explanation:

Let the two consecutive odd integers be x and x + 2.

Now,

The given statement is

x^2 + 3 \times (x+2)=24\\x^2 + 3x+6-24 = 0 \\x^2 + 3x-18 = 0\\x^2+6x-3x-18=0\\x(x+6)-3(x+6)=0\\(x-3)(x+6)=0\\x=3,-6

Taking x=3.

Hence, two consecutive odd integers are 3 and 5.

7 0
3 years ago
Each letter of the word "supercalifragilisticexpialidocious" is placed into a bag and drawn at 3 times, replacing the letter aft
Makovka662 [10]

Answer:

P(X ≥ 1) = 0.50

Step-by-step explanation:

Given that:

The word "supercalifragilisticexpialidocious" has 34 letters in which 'i' appears 7 times in the word.

Then; the probability of success = 7/34 = 0.20588

Using Binomial distribution to determine the probability; we have:

P(X = x)  = ^nC_x  \ \beta^x   \  (1 - \beta)^{n-x}

where;

x = 0,1,2,...n    and    0  <  β   <   1

and x represents the  number of successes.

However; since the letter is drawn thrice; the probability that the letter "i" is drawn at least once can be computed as:

P(X ≥ 1) = 1 - P(X< 1)

P(X ≥ 1) = 1 - P(X =0)

P(X \ge 1) =  1 - \bigg [ {^3C__0} (0.21)^0 (1-0.21)^{3-0} \bigg]

P(X \ge 1) =  1 - \bigg [ 1 \times 1 (0.79)^{3} \bigg]

P(X ≥ 1) = 1 - 0.50

P(X ≥ 1) = 0.50

4 0
3 years ago
What is the vertex form for y=-3x^2+30x+7
Ad libitum [116K]
X=-1/29 it’s divided the 1 /29
8 0
3 years ago
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