Answer:
The answer is 0.96
Step-by-step explanation:
Answer:
The equation 4x-7x=9 simplifies into x=-3, which is a horizontal line. A perpendicular line would be vertical, and the equation for vertical lines is y=b, b being a constant. In this case on the point (4,3), y is 3, so the equation of the line is y=3.
Answer:
79.59 units ³
Step-by-step explanation:
As we know, Volume of cone = ⅓πr²h
<u>Given</u>
r = 2 units
h = 19 units
π= 22/7
.
![\frac{1}{3} \times \frac{22}{7} \times 2 \times 2 \times 19](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%7D%20%20%5Ctimes%20%20%5Cfrac%7B22%7D%7B7%7D%20%20%5Ctimes%202%20%5Ctimes%202%20%5Ctimes%2019)
= 79.59 units ³
Step-by-step explanation:
Line is passing through the points:
Equation of line in two point form is given as:
![\frac{y -y_1 }{y_1 -y_2 } = \frac{x -x_1 }{x_1 -x_2 } \\ \\ \therefore \frac{y -3}{ 3 -5} = \frac{x -(-2) }{-2 -2} \\ \\ \therefore \frac{y -3}{ - 2} = \frac{x -(-2) }{-4} \\ \\ \therefore \frac{y - 3}{1} = \frac{x +2}{2} \\ \\ \therefore \: y-3= \frac{x}{2} + \frac{2}{2} \\ \\\therefore \: y= \frac{x}{2} + 1 +3\\ \\ \huge \red{ \boxed{\therefore \: y= \frac{1}{2} \:x+ 4}}\\ is \: the \: required \: equation \: of \: line.](https://tex.z-dn.net/?f=%5Cfrac%7By%20-y_1%20%7D%7By_1%20-y_2%20%7D%20%3D%20%5Cfrac%7Bx%20-x_1%20%7D%7Bx_1%20-x_2%20%7D%20%5C%5C%20%5C%5C%20%5Ctherefore%20%5Cfrac%7By%20-3%7D%7B%203%20-5%7D%20%3D%20%5Cfrac%7Bx%20-%28-2%29%20%7D%7B-2%20-2%7D%20%5C%5C%20%5C%5C%20%5Ctherefore%20%5Cfrac%7By%20-3%7D%7B%20-%202%7D%20%3D%20%5Cfrac%7Bx%20-%28-2%29%20%7D%7B-4%7D%20%5C%5C%20%5C%5C%20%5Ctherefore%20%5Cfrac%7By%20-%203%7D%7B1%7D%20%3D%20%5Cfrac%7Bx%20%2B2%7D%7B2%7D%20%5C%5C%20%5C%5C%20%5Ctherefore%20%5C%3A%20y-3%3D%20%5Cfrac%7Bx%7D%7B2%7D%20%2B%20%5Cfrac%7B2%7D%7B2%7D%20%5C%5C%20%5C%5C%3C%2Fp%3E%3Cp%3E%5Ctherefore%20%5C%3A%20y%3D%20%5Cfrac%7Bx%7D%7B2%7D%20%2B%201%20%2B3%5C%5C%20%5C%5C%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%20%5Chuge%20%5Cred%7B%20%5Cboxed%7B%5Ctherefore%20%5C%3A%20y%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5C%3Ax%2B%204%7D%7D%5C%5C%20is%20%5C%3A%20the%20%5C%3A%20required%20%5C%3A%20equation%20%5C%3A%20of%20%5C%3A%20line.)