For this we will use equation that gives us equation of line that goes through 2 given points.
that equation is:
now we implement our given coordinates.
let Q be point 1 and R be point 2
y - 1 = 6/2(x - 0)
y - 1 = 3x
Answer is b.
Answer:
The roots of the given equation are x = 0 and x = -8.
General Formulas and Concepts:
<u>Algebra I</u>
Terms/Coefficients
Quadratic Equations
- Solving quadratic equations
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify.</em>
y = x² + 8x
<u>Step 2: Find Roots</u>
- [Quadratic] Factor: y = x(x + 8)
- [Quadratic] Set up [Solve]: 0 = x(x + 8)
- [Quadratic] Define: x = 0, -8
∴ the roots of the quadratic equation y = x² + 8x is equal to 0 and -8.
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Topic: Algebra I
Answer:
(x) = │ x - 4│+ 3
Step-by-step explanation:
Selection C is appropriate.
_____
The change in x for the offered points is -6, -2, 16, 20, so the slope of 1/2 will make the change in y be -3, -1, 8, 10. When added to 5, these values are 2, 4, 13, 15. Only 13 matches the second coordinate of the given answer, so only (9, 13) will be a point on the line.
