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yaroslaw [1]
3 years ago
14

mia's hair was 17 inches long, two years later it was 30 inches long. What was the percent increase, to the nearest hundredth, o

f mia’s hair length?
Mathematics
1 answer:
nata0808 [166]3 years ago
6 0
22.1% this could be right someone check with me lol
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Help me plz quick only 5 mins​
solniwko [45]

Answer:

line B'C' = 1

m<C'D'A' = 90 degrees (it is still a rectangle)

Step-by-step explanation:

Dilation of coordinates:

Original: d:(3,2), a:(3,4), b:(7,4), c:(7,2)

Divide all numbers by 2.

Altered: d:(1.5,1), a:(1.5,2), b:(3.5,2), c:(3.5,1)

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Renee can see a 25 square foot quilt in 16 hours. Genera can sew the same size quilt in 12 hours. How long would it take them to
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28 hours because they are too long from each other

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What is speed of sound in air at 100 degree celcius?​
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386m/s is the answer to your question

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3 years ago
The Rocky Mountain district sales manager of Rath Publishing Inc., a college textbook publishing company, claims that the sales
andrezito [222]

Answer:

t=\frac{44-42}{\frac{1.9}{\sqrt{40}}}=6.657    

p_v =P(t_{(39)}>6.657)=3.17x10^{-8}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 42 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=44 represent the sample mean

s=1.9 represent the sample standard deviation

n=40 sample size  

\mu_o =42 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 42, the system of hypothesis would be:  

Null hypothesis:\mu \leq 42  

Alternative hypothesis:\mu > 42  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{44-42}{\frac{1.9}{\sqrt{40}}}=6.657    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_{(39)}>6.657)=3.17x10^{-8}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 42 at 1% of signficance.  

3 0
3 years ago
2x^2-5x-3=0 ? im working on factoring and im not sure how to solve this
Whitepunk [10]
2x²-5x-3 = 0

(2x+1) (x-3) = 0

2x+1 = 0
2x = -1

x = -½

x-3 = 0

x = 3

then x = -½ , x= 3
3 0
2 years ago
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