Answer:
public static boolean isReverse(int [ ]a, int [ ]b ){
for (int i=0;i<a.length;i++)
{
if(!(a[i] == b[a.length-i-1]))
return false;
}
return true;
}
Explanation:
Using a for loop, we go through the elements of the first array. The if comapres and checks if any of the values are not the same as the appropriate value on the other array, if it is so, then it is not a reverse, and we return false. else we return true.
Answer:
<h3><u>Microblogging </u></h3>
- <u>One of the best-known channels in the microblogging world. Twitter is a quick and convenient way to share short posts, GIFs, article links, videos and more. Pinterest: Companies on Pinterest link to products, articles and other useful information for </u><u>audiences </u><u>.</u>
Explanation:
<h2>Hope this helps you !! </h2>
Answer:
Printing Quality, Price, If it van vonnect to my laptop or nay devices.
Answer:
Explanation:
The following program was written in Java. It creates a loop that asks the user for numbers. If it can convert it to an integer it accepts it and adds it to the sum variable otherwise it ouputs that it is not a valid number. Once all 10 integers are added it prints the Average of the values entered.
import java.util.ArrayList;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int sum = 0;
while (count != 10) {
System.out.println("Enter a number: ");
String answer = in.nextLine();
try {
int intAnswer = Integer.parseInt(answer);
sum += intAnswer;
count += 1;
} catch (NumberFormatException e) {
System.out.println("Not a valid number.");
}
}
int average = sum / count;
System.out.println("Average: " + average);
}
}
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