Answer:
C = 3
Explanation:
The maximum number of physical memory accesses that may be caused by this single instruction is ; 3
This is because In the case of loading two values into R2 and R3 there is need for their memories to be accessed and after execution R1 value there will be a write back into memory hence another memory is also accessed and that makes the number of Physical memories accessed to be three(3) in Total
Answer:
501.
Explanation:
In Transmission Control Protocol (TCP), sending and receiving of data is done as byte. These bytes are eventually grouped into packets referred to as segment.
The sequence number of the segment if all data is sent in only one segment is the same as the first byte of that segment.
In this scenario, a user datagram connection is sending 500 bytes to a client and the first byte is numbered 501. Thus, if all data is sent in only one segment, the sequence number of the segment is 501. The 501 represents the initial segment number (ISN).
However, assuming the same data was sent in five (5) segments. The sequence number would be;
First segment (1st) = 501.
Second segment (2nd) = 1501.
Third segment (3rd) = 2501.
Fourth segment (4th) = 3501.
Fifth segment (5th) = 4501.
Answer: Hi!, hope this helps. :)
Explanation: After you proofread and do a first edit of you paper, you should either read it out loud or have someone read it back to you. Hearing the paper out loud is one of the best ways to find unclear wordings. You should also do revising. You should make sure your writing meets the requirements of the writing catagory and maybe even get a rubric of the requirements.
This is the best answer I can give, I hope this answers your question! Try to make me the brainliest if you can.
Answer:
C, stealing someone else's personal data.
