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Readme [11.4K]
3 years ago
13

The length of a rectangle is 2 less than twice the width. The perimeter of the rectangle is 38. Find the length and the width of

the rectangle.
Mathematics
1 answer:
hjlf3 years ago
6 0

Answer:

YEET A DOG

Step-by-step explanation:

YEETING A DOG GIVES U COOL POINTS LOLOLOLOLOLOLOLOLOLOLOL

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How do I solve this problem
VladimirAG [237]
Hi there!

Since, The length of th' tangents drawn from an external point to a circle are equal.

Therefore, we draw following conclusions :-

• CF = EC = 6 cm
• BE = DB = 16 cm
• AD = FA = 12 cm

Now,

According to th' question, Perimeter of ΔΑΒC :-

AB + BC + AC

⇒ AD + DB + BE + EC + CF + FA

⇒ 12 cm + 16 cm + 16 cm + 6 cm + 6 cm + 12 cm = 68 cm

Hence,
The Perimeter of ΔΑΒC is 68 cm

~ Hope it helps!
7 0
3 years ago
Write the equation of the line that passes through the points (7,9) and
nevsk [136]

Step-by-step explanation:

9 = a7 + b

-2 = a9 + b

b = 9-7a and b = - 2-9a

9 - 7a = - 2-9a

2a = - 11

a = - 5.5

b = 9 - 5.5*7 = - 29.5

y = -5.5x - 29.5

5 0
3 years ago
Suppose you want to buy 100 pens. You can buy 100 pens at a 10% discount at one store where the price is $6.99 per pen. And you
andriy [413]

Answer:

a. $629.10

b. $635.80

c. $6.70

Step-by-step explanation:

The first thing we need to do is turn these percentages into decimal values by dividing them by 100, this would make 10% into 0.10 and 15% into 0.15. Now we can make the following equations to calculate the total by multiplying the 100 pens by the individual pricer per pen, and then multiplying that product by the 1 minus the discount percentage.

A)    (100 * 6.99) * (1 - 0.10) = x

          699 * 0.90 = x

              $629.10 = x

B)    (100 * 7.48) * (1 - 0.15) = x

          748 * 0.85 = x

              $635.80 = x

C)   635.80 - 629.10 = $6.70

The difference is $6.70 more for the 100 pens in the second store.

   

7 0
3 years ago
PLS HELP ASAP I WILL GIVE BRAINLIST
jarptica [38.1K]

Answer:

Step-by-step explanation:

What's a brainlist?

6 0
3 years ago
two triangles have side lengths of 3 inches, 4 inches, and 5 inches, is it possible to draw two different triangles that meet th
Alenkinab [10]

Answer:

It is impossible to draw two different triangles with these criteria.

Step-by-step explanation:

The 3,4,5 triangle is a Pythagorean triplet, but if it was said to be 6,8,10, then yes two different triangles can be made, same with any other multiple of a 3,4,5 right triangle. The 3,4,5 triangle is in its reduced form causing there to be no other triangles that can be made that still function as a triangle through the theorem of triangles where the hypotenuse has to be bigger than either side length.

7 0
3 years ago
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