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sweet-ann [11.9K]
3 years ago
13

Select the exclusion that fits best with this problem. 13x^6/51x^4

Mathematics
1 answer:
Damm [24]3 years ago
5 0

ANSWER

x \ne0

EXPLANATION

The given problem is

\frac{13 {x}^{6} }{ 51 {x}^{4}  }

This is defined if and only if

x \ne0

Even the given expression can be simplified to obtain:

\frac{13 {x}^{2} }{ 51}

The exclusion is

x \ne0

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A line with a slope of -1 passes through the point (0,0). What is its equation in slope-intercept form?​ Please answer quickly.
rusak2 [61]

Answer:

y = -x

Step-by-step explanation:

The line has a slope of -1 and it passes through point (0,0)

Taking another point (x,y) on the line;

Slope = change in y ÷ change in x

For our case; slope = \frac{y - 0}{x - 0} = -1

Cross multiplying this gives;

y = -x

4 0
3 years ago
Y= x +2<br> x^2 +y^2=10<br><br> solve using any method
Jobisdone [24]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

(-3, -1) and (1, 3)

»»————- ★ ————-««  

Here’s why:  

  • I have graphed the two equations given on a graphing program.
  • When graphed, they pass at points (-3, -1) and (1,3). Therefore, they are the solutions to the system.

⸻⸻⸻⸻

See the graph attached.

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

7 0
3 years ago
Read 2 more answers
Question 3
Crank

Step-by-step explanation:

Given that,

The mass of a patient = 70 kg

A 70kg patient has approximately 8 pints of blood.

The patient donates 470mL of blood.

We know that,

1 pint = 568 mL

8 pints = 4544 mL

Required fraction,

\dfrac{470}{4544}=0.1\\\\=\dfrac{1}{10}

So, the required fraction is approximately \dfrac{1}{10}.

4 0
3 years ago
C= 5/9 (F−32)
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Answer:

C = 5/9 (F - 32)

This is a temperature scale change comparison.

By this we understand, that ,

1°C = 5/9°F

Which is equal to, 5/9°F = 1°C

These two statements are satisfied by I. and II.

So, the correct answers are, I. and II.

If my answer helped, kindly mark me as the brainliest!

Thank You!!

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3 years ago
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I need to know the sides of the trapezoid in order to find the perimeter
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