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sweet-ann [11.9K]
3 years ago
13

Select the exclusion that fits best with this problem. 13x^6/51x^4

Mathematics
1 answer:
Damm [24]3 years ago
5 0

ANSWER

x \ne0

EXPLANATION

The given problem is

\frac{13 {x}^{6} }{ 51 {x}^{4}  }

This is defined if and only if

x \ne0

Even the given expression can be simplified to obtain:

\frac{13 {x}^{2} }{ 51}

The exclusion is

x \ne0

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Does this graph represent a function? Why or why not?
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Answer:

Option D is the correct answer

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2 years ago
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
2 years ago
A bag contains 4 red marbles, 3 green marbles, and 2 yellow marbles. The probability of randomly picking a yellow marble is . Wh
djverab [1.8K]
You would add the red marbles and green marbles together and which would be 7 the get the total marbles would be 9 so the answer would be 7/9 or 78%
8 0
3 years ago
At the district competition for 5th grade jump-roper of the year, the following number of jumps without stopping were recorded p
deff fn [24]
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The median of the number of jumps is the mean of the 12th and 13th term.
                          265 
5 0
3 years ago
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