Answer:
The correct answers is: I would predict that animals with longer loops of Henle would be able to concentrate their urine more than animals with shorter loops, and thus they would more likely survive in desserts and other dry areas.
Explanation:
The<em> Loop of Henle</em> is a tubule system that connects the proximal convoluted tubule to the distal convoluted tubule in a nephron, the functional and structural unit of the kidney. Its primary job is to establish a concentration gradient in the kidney's medulla by creating a high urea concentration deep in the medulla using a countercurrent multiplier system that uses electrolyte pumps. Through this mechanism, <u><em>water is reabsorbed to concentrate the urine and impede dehydration</em></u>.
The length of the loops of Henle is of great importance for the countercurrent multiplier system - <u>the longer they are, the more concentrated the urine can get</u>. Therefore, animals with longer loops can survive better in habitats where there is not much water around.
Answer:
I think the correct answer is D
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Answer:
The correct answer is 160.
Explanation:
Based on the given question, the total number of fruit flies is 1000, of which red eye flies are 640. Thus, the number of sepia eye flies will be 1000-640 = 360.
On the basis of the Hardy-Weinberg equation, p+q = 1, in which p is the rate of recurrence of one allele, that is, dominant and q is the rate of recurrence of the other allele, that is, recessive.
q^2 for the population is 360/1000 = 0.36, q = 0.6.
Therefore, p = 1-q = 1-0.6 = 0.4.
The frequency of homozygous dominant allele is denoted by p^2 = 0.16.
Hence, the number of homozygous dominant for red eye color would be 16% of 1000 which will be equal to 160.
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