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lions [1.4K]
2 years ago
15

A map has a scale of 1.5 inches =9 miles

Mathematics
1 answer:
lawyer [7]2 years ago
8 0

Answer:

I don’t know lol

Step-by-step explanation:

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Section B
EastWind [94]
Divide $2769 by $9 and you get 306.6 but you can’t just buy .6 of a toy so that leaves you at 306 whole toys and 306x9 is $2754 so you would have $15 leftover
7 0
2 years ago
Write 5(6x+4)-2(5x-2) in the form a(bx+c) where a,b and c integers and a>1
Pavel [41]

Answer:

4(5x + 6)

Step-by-step explanation:

To start, let's expand things out, as we cannot learn anything from this form. We get 30x + 20 - 10x + 4, or 20x + 24. To find the GCD (Greatest Common Divisor), we take the terms and try to find the number (or term) that divides them. It must be a constant, because of the 24, and 4 goes into 20 and 24. So, our final answer is 4(5x + 6).

5 0
3 years ago
Read 2 more answers
Help I’m struggling badly in math
Fynjy0 [20]

Answer:

bran to blueberry: 4:1

banana nut to bran: 1 to 2

total to corn: 12 muffins to 5 muffins

bran to total: 1/3

Step-by-step explanation:

hope that helped.

5 0
2 years ago
In your own words, write a verbal expression for the following algebraic expression.<br> 18p
maxonik [38]

Step-by-step explanation:

18p is a multiplication expression in itself.

It could be written as 18 x p. I am confused on what you mean as 'verbal' so i'm gonna take a wild guess and say word form.

eighteen times p???

Sorry if it's wrong.

6 0
3 years ago
Add. (3b + 5) + (2b + 4)
zaharov [31]

Answer:

\huge{ \fbox{ \sf{5b + 9}}}

Step-by-step explanation:

\star{ \text{( \: 3b + 5) + (2b + 4)}}

\text{Step \: 1 \:  :  \sf{Remove \: the \: unnecessary \: parentheses}}

\text{When \: there \: is \: a \: ( + ) \: in \: front \: of \: an \: expression \: in \: parentheses \:, there \: is \: no \: need \: to \: change \: the \: sign \: of \: each \: term \: in \: the \: expression.}

\text{That \: means, \: the \: expression \: remains \: the \: same. \: Just \: you \: have \: to \: remove \: the \: parentheses.}

\mapsto{ \sf{3b + 5 + 2b + 4}}

\text{Step \: 2 \:  : Collect \: like \: terms.}

\text{Like \: terms \: are \: those \: which \: have \: the \: same \: base.}

\mapsto{ \sf{3b + 2b + 5 + 4}}

\mapsto{ \sf{5b + 5 + 4}}

\text{ Step \: 3 \:  :  \sf{Add \: the \: numbers : 5 \: and \: 4}}

\mapsto{ \boxed {\sf{ {5b + 9}}}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

4 0
2 years ago
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