I believe the answer to your question is
Yes, you would get two triangles that have the same shape and size
Answer:
The answer is (d) ⇒ e = 1/7 , k = 12 , conic ellipse
Step-by-step explanation:
∵ r = ek/(1 ± ecosФ)
∵ r = 12/(7 - cosФ) ⇒ ÷ 7 up and down
∴ r = 12/7 ÷ 1 - 1/7 (cosФ)
∴ e = 1/7
∵ 12/7 = ke ⇒ 12/7 = k(1/7)
∴ k = 12
∵ 0 < e < 1
∴ The conic is ellipse
Step-by-step explanation:
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