Answer:

Step-by-step explanation:
Odd numbers from the list are 75, 189, and 315.
75, 189, and 315, are composite numbers.
Prime factorization of 75 = 3 × 5 × 5
Prime factorization of 189 = 3 × 3 × 3 × 7
Prime factorization of 315 = 3 × 3 × 5 × 7
315 is an odd number, and a composite number that is divisible by 3 different prime numbers.
Answer:
P(1.5, 3.5)
Step-by-step explanation:
We need to find the average of the x and y coordinates. We do this by adding the two values, then dividing by two:
P(x1 + x2/ 2, y1 + y2/2) = P(1 + 2/ 2, 2 + 5/ 2) = P(3/2, 7/2) = P(1.5, 3.5)
These are our coordinates!
Answer: 12
Step-by-step explanation:
Answer: the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23
Step-by-step explanation:
Formula for margin of error : 
, where z* = Critical z-value.
Given: population standard deviation = 11.5 ounces
Sample size = 20
Z value for 90% confidence level = 1.645
margin of error (E) = 

Hence, the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23