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3 years ago

When converting a percent to a decimal, will there always be two digits after the decimal point? Explain

Mathematics

2 answers:

Goshia [24]3 years ago

4 0

Answer:

Step-by-step explanation:

For example, 50% can be written as just 0.5

rjkz [21]3 years ago

4 0

Dam shawty looking good

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What is the quotient

mario62 [17]

Answer:

The quotient is 3x - 11 + 60/(x + 5) ⇒ 2nd answer

Step-by-step explanation:

* We will use the long division to solve the problem

- The dividend is 3x² + 4x + 5

- The divisor is x + 5

- The quotient is the answer of the division

- If the divisor not a factor of a dividend, the quotient has

a remainder

* Lets solve the problem

- At first divide the first term in the dividend by the first term in

the divisor

∵ 3x² ÷ x = 3x

- Multiply the divisor by 3x

∴ 3x (x + 5) = 3x² + 15x

-Subtract this expression from the dividend

∴ 3x² + 4x + 5 - (3x² + 15x) = 3x² + 4x + 5 - 3x² - 15x = -11x + 5

- Divide the first term -11x in the new dividend by the first

term x in the divisor

∴ -11x ÷ x = -11

- Multiply the divisor by -11

∴ -11(x + 5) = -11x - 55

-Subtract this expression from the new dividend

∴ -11x + 5 - (-11x - 55) = -11x + 5 + 11x + 55 = 60

∴ The quotient is 3x - 11 with remainder = 60

* The quotient is 3x - 11 + 60/(x + 5)

5 0

3 years ago

There are six households in a rural community. Each household earns $40,000 per year. Suppose that a new resident builds a mansi

dusya [7]

Answer:

Median income has not changed

Mean income has increased

Step-by-step explanation:

Initial number of houses = 6

Earning per household = $40,000

The initial mean :

$(40,000 * 6) / 6 = $40000

Initial median :

40000, 40000, 40000, 40000, 40000, 40000

= 1/2(n+1)th term,

Median = 40000

A 7th household earns 4,000,000

Mean = ((40000*6) + 4,000,000) / 7 = $605,714

Median = 1/2(n+1)th term

40000, 40000, 40000, 40000, 40000, 40000, 4000000

Median = 4th term = 40000

7 0

3 years ago

3. Decide whether each equation is true or false, and explain how you know.

BARSIC [14]

Answer:

a.false

b.true

c.false

d.I really can't get about it.

e.false

Step-by-step explanation:

So,here;

a.9.9.3=35 is given

or,243=35 (which is false)

b.7+7+7=3+3+3+3+3+3+3

or,21=21 (which is true)

c.2/3/2=2/3

or,2*2/3=2/3

or,4/3=2/3(which is false)

e.6+6+6=63

or,18=63 (which is false)

5 0

3 years ago

I toss an unfair coin 12 times. This coin is 65% likely to show up heads. Calculate the probability of the following.

mars1129 [50]

Answer:

a. 0.0368

b. 0.99992131

c. 0.2039

d. 0.0048

e. 0.6533

Step-by-step explanation:

Let the probability of obtaining a head be p = 65% = 13/20 = 0.65. The probability of not obtaining a head is q = 1 - p = 1 -13/20 = 7/20 = 0.35

Since this is a binomial probability, we use a binomial probability.

a. The probability of obtaining 11 heads is ¹²C₁₁p¹¹q¹ = 12 × (0.65)¹¹(0.35) = 0.0368

b. Probability of 2 or more heads P(x ≥ 2) is

P(x ≥ 2) = 1 - P(x ≤ 1)

Now P(x ≤ 1) = P(0) + P(1)

= ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹

= (0.65)⁰(0.35)¹² + 12(0.65)¹(0.35)¹¹

= 0.000003379 + 0.00007531

= 0.0007869

P(x ≥ 2) = 1 - P(x ≤ 1)

= 1 - 0.00007869

= 0.99992131

c. The probability of obtaining 7 heads is ¹²C₇p⁷q⁵ = 792(0.65)⁷(0.35)⁵ = 0.2039

d. The probability of obtaining 7 heads is ¹²C₉q⁹p³ = 220(0.65)³(0.35)⁹ = 0.0048

e. Probability of 8 heads or less P(x ≤ 8) = ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹ + ¹²C₂p²q¹⁰ + ¹²C₃p³q⁹ + ¹²C₄p⁴q⁸ + ¹²C₅p⁵q⁷ + ¹²C₆p⁶q⁶ + ¹²C₇p⁷q⁵ + ¹²C₈p⁸q⁴

= = ¹²C₀(0.65)⁰(0.35)¹² + ¹²C₁(0.65)¹(0.35)¹¹ + ¹²C₂(0.65)²(0.35)¹⁰ + ¹²C₃(0.65)³(0.35)⁹ + ¹²C₄(0.65)⁴(0.35)⁸ + ¹²C₅(0.65)⁵(0.35)⁷ + ¹²C₆(0.65)⁶(0.35)⁶ + ¹²C₇(0.65)⁷(0.35)⁵ + ¹²C₈(0.65)⁸(0.35)⁴

= 0.000003379 + 0.00007531 + 0.0007692 + 0.004762 + 0.01990 + 0.05912 + 0.1281 + 0.2039 + 0.2367

= 0.6533

3 0

3 years ago

Write the expression <br> 3x-(2-4x) in standard form

Llana [10]

7x-2 is how it’s written in standard form

4 0

3 years ago