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Dmitrij [34]
2 years ago
11

Solve. x - 2y + 32 = 8 3y +z = 12 -2x + 2z=-4

Mathematics
1 answer:
konstantin123 [22]2 years ago
5 0

Answer:

Solve the system using the linear combination method. -x + 2y +z = 4. -X +24+7=4. -24-62=-36 x + y + z = 5 + X+ 4+ Z:5. -x + 3y + 2z = 8. +12y +92=39.

Step-by-step explanation:

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Solve for x.<br> 5x – 4 ≥ 12<br> OR<br> 12x + 5 ≤ -4
VARVARA [1.3K]

Answer:

x≥16/5

Step-by-step explanation:

5x-4≥12

5x≥16

x≥16/5

4 0
2 years ago
Mark all the statements that are true <br> a) the domain for this function is the set {3}
telo118 [61]

Answer:

the answer is 6 statements

Step-by-step explanation:

8 0
2 years ago
What are the domain restrictions of the expression g2−7g+10g3−6g2+8g ? Select each correct answer.
Sauron [17]

Answer with Step-by-step explanation:

We are given that an expression

f(g)=\frac{g^2-7g+10}{g^3-6g^2+8g}

We have to find domain restriction of the given function.

f(g)=\frac{(g-5)(g-2)}{g(g-4)(g-2)}

Domain restriction means : It is that value of x when substitute in function then  function will  not defined.

It means it is that values which makes denominator zero.

From given function we can see that

When substitute g=0 then it makes denominator zero.

Hence, the function is not defined at g=0

Substitute g=4

Then, it makes denominator zero.

Hence, function is not defined  at g=4

Substitute g=2

Then,it  makes denominator zero.

Hence, function is not defined  at g=2

Therefore, the function is defined for all values of g except g=0, g=2 and g=4

5 0
3 years ago
Question 20 (5 points)
Sloan [31]

Answer:

Question 20   3 < c < 9

Question 21    2.5

Step-by-step explanation:

hope this helps u

3 0
2 years ago
Simplify (-32) ÷ (-4)
Keith_Richards [23]

\bold{Hey\ there!}

\bold{Guide\downarrow}

\bold{Negative} & \bold{Negative} =\bold{Positive}

\bold{Positive} & \bold{Negative} = \bold{Negative}

\bold{Positive} & \bold{Positive} = \bold{Positive}

\bold{Negative} & \bold{Positive} = \bold{Negative}

\bold{(-32)\div(-4)}

\bold{=32\div4}

\bold{=8}

\boxed{\boxed{\bold{Answer: 8}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

3 0
3 years ago
Read 2 more answers
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