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3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Mathematics

2 answers:

aleksandr82 [10.1K]3 years ago

5 0

Hello, I Am BrotherEye

Answer:

Median = 46.5

Minimum = 32

Maximum = 62

Lower quartile = 38

Upper quartile = 59

Step-by-step explanation:

Before we can proceed to solving any of these, it is best you arrange your data first from least to greatest

32 34 37 39 41 45 48 53 58 60 61 62

First we have the median. The Median is the middle value. In this case we an even number of data, which is 12 data points. The middle value of the data would be found in between the 6th and 7th data point:

45 and 48

To get the middle value, you need to solve for the value that is in the middle of 45 and 48 by getting the sum of both numbers and dividing it by two.

45 + 48 = 93

93 ÷ 2 = 46.5

The minimum and maximum value is merely the least and greatest number.

Here we have:

Minimum = 32

Maximum = 62

To get the lower and upper quartiles, just remember that quartiles divide the data into 4 equal parts. All you need to do is find the value that is in between each quarters of the data:

Q1 (Lower) Q2(Median) Q3(Upper)

32 34 37 | 39 41 45 | 48 53 58 | 60 61 62

Like the median, we will find the value that comes in between each quarter.

37 + 39 = 76

76 ÷ 2 = 38

Lower quartile = 38

Q3:

58 + 60 = 118

118 ÷ 2 = 59

Upper quartile = 59

alisha [4.7K]3 years ago

3 0

Answer:

what the person said up there

Step-by-step explanation:

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