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xxTIMURxx [149]
3 years ago
15

Moe is 12 years older than Barney .three years ago ,moe was five times as old as Barney .how old is Barney now

Mathematics
2 answers:
Aneli [31]3 years ago
4 0
The answer is 7 years old.
inessss [21]3 years ago
4 0
M=12+b

m-3=5(b-3)
sub 12+b for m
12+b-3=5(b-3)
expand and combine like terms
b+9=5b-15
minus 4b both sides
9=4b-15
add 15 both sidse
24=4b
divide by 4
6=b

barney is 6
moe is 18
 3 years ago, barney is 3 and moe is 15, 3*5=15


barney is 6 now
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irga5000 [103]

\huge\boxed{18\ \text{points}}

We'll represent Louise's, Tammy's, Delores's, and Sheryl's point values with x, x+1, x+2, and x+3 respectively since each one is 1 point more than the last.

Add all of these values up and set it all equal to 78.

x+x+1+x+2+x+3=78

Now, simplify.

4x+6=78

Subtract 6 on both sides.

\begin{aligned}4x+6-6&=78-6\\4x&=72\end{aligned}

Divide both sides by 4.

\begin{aligned}\frac{4x}{4}&=\frac{72}{4}\\x&=\boxed{18}\end{aligned}

Since Louise's score is x, the answer is 18.

<h3>Double-checking</h3>

To verify our answer, add the point totals 18, 19, 20, and 21.

This equals 78, so we can be sure the answer is correct.

5 0
1 year ago
If value of a+b=7and ab=12then find the value of a and b
LiRa [457]

a+b = 7

ab =12

we know that

a and b = ab – a+b

= 12 –7

= 5 ans

3 0
3 years ago
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These triangles are congruent by which triangle congruence postulate ?
svp [43]
(a) SSS (side side side)
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2 years ago
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What’s the multipcative inverse of 1/4
LuckyWell [14K]

Hey!

Answer:

4/1

Step-by-step explanation:

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Hope This Helps :)

7 0
3 years ago
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Solve for x and y.<br><br> 4x-3y=16<br> -2x+4y=-2<br><br> DUE 2/7/17!
Trava [24]
\left \{ {{4x-3y=16\:(I)} \atop {-2x+4y=-2\:(II)}} \right.

<span>Multiply the 2nd equation by (-4). This will eliminate the x's when you add the two new equations together.
</span>\left \{ {{4x-3y=16\:\:\:\:\:\:\:\:\:\:} \atop {-2x+4y=-2\:*(-4)}} \right.
\left \{ {{\diagup\!\!\!\!4x-3y=16} \atop {-\diagup\!\!\!\!4x+8y=-4}} \right.
--------------------
5y = 12
\boxed{\boxed{y =  \frac{12}{5}}}\end{array}}\qquad\quad\checkmark

Let's replace the value found in the first equation:
4x-3y=16\:(I)
4x-3*( \frac{12}{5}) =16
4x -  \frac{36}{5} = 16
least common multiple (5)
\frac{20x}{\diagup\!\!\!\!5} - \frac{36}{\diagup\!\!\!\!5} = \frac{80}{\diagup\!\!\!\!5}
20x - 36 = 80
20x = 80 + 36
20x = 116
x = \frac{116}{20} \frac{\div4}{\div4} \to\: \boxed{\boxed{x = \frac{29}{5} }}\end{array}}\qquad\quad\checkmark



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3 years ago
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