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dangina [55]
3 years ago
9

The mean of a normally distributed dataset is 12, and the standard deviation is 2.

Mathematics
1 answer:
Schach [20]3 years ago
5 0
So lets do it like this:
z = (X-Mean)/SD 
<span>z1 = (8-12)/2 = - 2 </span>
<span>z2 = (16-12)/2 = + 2 </span>
<span>According to the Empirical Rule 68-95-99.7 </span>
<span>Mean more or less 2SD covers 95% of the values </span>
So t<span>he percentage of data points falling between 8 and 16 = 95%
</span>I hope this can help
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Suppose that we are testing a coin to see if it is fair, so our hypotheses are: H0: p = 0.5 vs Ha: p ≠ 0.5. In each of (a) and (
aleksley [76]

Answer:

H_0: p = 0.5\\H_a: p \neq 0.5

a. We get 56 heads out of 100 tosses.

We will use one sample proportion test  

x = 56

n = 100

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{56}{100}

\widehat{p}=0.56

Formula of test statistic =\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

                                       =\frac{0.56-0.5}{\sqrt{\frac{0.5(1-0.5)}{100}}}

                                       =1.2

refer the z table for p value

p value = 0.8849

a.  We get 560 heads out of 1000 tosses.

We will use one sample proportion test  

x = 560

n = 1000

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{560}{1000}

\widehat{p}=0.56

Formula of test statistic =\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

                                       =\frac{0.56-0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}

                                       =3.794

refer the z table for p value

p value = .000148

p value of part B is less than Part A because part B have 10 times the number the tosses.

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2 years ago
X = 0.5<br> Solve please
faltersainse [42]

Answer:

2x-1=0

Step-by-step explanation:

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10x-5=0

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4 0
3 years ago
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