9/16+ 1/2
= 9/16+ (1*8) / (2*8)
= 9/16+ 8/16 (common denominator is 16)
= (9+8)/16
= 17/16
= (16+1)/16
= 16/16+ 1/16
= 1+ 1/16
= 1 1/16
The final answer is 1 1/16~
Answer: 57.5%
Step-by-step explanation:
Because....
23/40 =
23 ÷ 40 =
0.575 =
0.575 × 100/100 =
0.575 × 100% =
(0.575 × 100)% =
57.5%
* <em>Therefor, the correct answer would be 57.5% .</em>
<em>* Hopefully this helps:) Mark me the brainliest:)!!!</em>
R = 0.9
A value of 0.9 would indicate that the correlation is positive. Since it's also close to the value 1, it would also tell us that the correlation of y and x is strong. Therefore, r = 0.9 would be a strong linear association in which y increases as x increases.
r = -1.0
Since the value of r is negative, this would mean that the correlation is also negative. Furthermore, the value of r is also at the minimum point which is -1.0 thus this would tell us that the correlation is a perfect linear association in which y decreases as x increases.
r = -0.6
Likewise, this r value is also negative thus allowing us to know that y will decrease as x increases. The value of r, which is -0.6, is also close to -1.0. This allows us to tell that it is a strong relationship. Therefore, r = -0.6 is a strong linear association in which y decreases as x increases.
r = 0.1
For this correlation, the r value is positive. This would indicate that the value of y will increase as x increases. Since the r value is only 0.1, we cannot say that it is a strong relationship since it is far from the maximum value for a perfect relationship which is 1. Therefore, r = 0.1 is a moderate linear association in which y increases as x increases.
(a) The radius of the circle is the distance the wave travels since it first formed, so if <em>g(t)</em> is the radius of the circle at time <em>t</em>, then it changes at a rate according to
d<em>g</em>/d<em>t</em> = 60 cm/s
Integrate both sides with respect to <em>t</em> to solve for <em>g</em> :
∫ d<em>g</em>/d<em>t</em> d<em>t</em> = ∫ (60 cm/s) d<em>t</em>
<em>g(t)</em> = (60 cm/s) <em>t</em> + <em>C</em>
but <em>C</em> = 0 since the radius at <em>t</em> = 0 must be 0.
<em>g(t)</em> = (60 cm/s) <em>t</em>
<em />
(b) The area of any circle with radius <em>r</em> is <em>πr</em> ². So
<em>f(r)</em> = <em>πr</em> ²
(c) The composition of <em>f</em> with <em>g</em> represents the area of water encircled by the wave at time <em>t</em> :
<em>(f</em> o <em>g)(t)</em> = <em>f(g(t))</em> = <em>π</em> <em>g(t) </em>²
Answer:
yes they are
Step-by-step explanation:
