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3 years ago

Given f(x) = 7x^9 find f^-1(x) Then state whether f^-1(x) is a function

Mathematics

1 answer:

Ghella [55]3 years ago

6 0

F-1(x) = -7x^9
Yes, it IS a function.

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Simplify X2-49 Over X2+9x+14

Stels [109]

Answer:

(x-7)/(x+2)

Step-by-step explanation:

(x-7)(x+7)/(x+7)(x+2)

(x-7)/(x+2)

7 0

3 years ago

(7 x 10^−12)(4 x 10^5) in scientific notation

Radda [10]

(7 x 10^−12)(4 x 10^5)
= (7x4) x 10^-7
= 28 x 10^-7
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4 years ago

How do you simplify this? x²y+xy² / y²+2/5 × xy

polet [3.4K]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

How do you simplify this?
x²y+xy² / y²+2/5 × xy

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

$\sf\frac{ { x }^{ 2 } y+x { y }^{ 2 } }{ { y }^{ 2 } + \frac{ 2 }{ 5 } \times xy } \\$

Factor the expressions that are not already factored.

_____

How to factorise :-

NUMERATOR $\downarrow$

$\sf \: x ^ { 2 } y + x y ^ { 2 }$

Factor out xy.

$\sf \: xy\left(x+y\right)$

DENOMINATOR $\downarrow$

$\sf{ y }^{ 2 } + \frac{ 2 }{ 5 } \times xy \\$

Factor out 1/5.

$\sf \: {\frac{1}{5}y\left(2x+5y\right)} \\$

_____

Continuing...

$\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)} \\$

Cancel out y in both the numerator and denominator.

$\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)} \\$

Expand the expression.

$\sf\frac{x^{2}+xy}{\frac{2}{5}x+y} \\$

This can further simplified to as $\downarrow$

$= \boxed{\boxed{\bf\frac{5x\left(x +y\right)}{2x+5y}}}$

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likoan [24]

Answer:

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Step-by-step explanation:

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maxonik [38]

6in would be the answer

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