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4 years ago

Are these all correct?

Mathematics

1 answer:

sladkih [1.3K]4 years ago

4 0

Problem 1) Line n is the line of symmetry (not line o) because we can fold the lower half to match up with the upper half. The folding line is over line n.

Problem 2) I agree. Nice work on getting the correct answer. The folding line is a vertical line through the center

Problem 3) It's hard to say for sure, but I think the top left corner is NOT reflective over any line of symmetry no matter how you rotate it. So I would uncheck that box. I agree with your other choices though. Great job with those.

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Given (x)=-x²+2x,determine<br> F'(x) using first principle

mote1985 [20]

Hello,
which principle?

f(x)=-x²+2x
==>f'(x)= -2x+2

You mean maybe this

$\lim_{h \to 0} \frac{f(x+h)-f(x) } {h}$

f(x+h)=-(x+h)²+2(x+h)= -(x²+2hx+h²)+2x+2h
f(x)=-x²+2x

$\lim_{h \to 0} \frac{f(x+h)-f(x) } {h}=\lim_{h \to 0}\frac{-2hx-h^2+2h}{h}=\lim_{h \to 0}\frac{-2x-h+2}{1}=-2x+2$

6 0

3 years ago

In 2015, the population of a small town in Florida is 95. If the population increases by 15% every year, approximately wha will

nevsk [136]

If you add 15%, you now have 115% of the total.

95(1.15)8

Make sure to only apply the exponent to 1.15, then multiply by 95.

6 0

3 years ago

At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

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Fofino [41]

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Cloud [144]

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