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Sphinxa [80]
3 years ago
12

Can u guys pls help me on this question and pls explain how u got the answer

Mathematics
1 answer:
Lady_Fox [76]3 years ago
8 0

Answer:

55.75

Step-by-step explanation:

find the area of 1 side using the base and height and divide that answer by 2

5x6=30     30 divided by 2=15

all sides are equal so each side is 15

the base you do the same thing.

base is 5, height is 4.3

4.3 x 5= 21.5

divide it by 2 10.75

side 1=15

side 2= 15

side 3=15

base 1= 10.75

add all together

55.75

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Help me please :( ill give u brainnlyyyyyyy :DDD
9966 [12]

Answer:

180 grams

Step-by-step explanation:

2 people = 5 ounces

6 people= 5*3= 15 ounces

1 ounce= 28 grams

15 ounces= 15*28 grams= 420 grams

There is 240 grams already on the weight, so

420- 240= 180 grams more of diced onions are required

6 0
3 years ago
HELPPPPPPP!!!!! PLEASEEEE!!!!
maksim [4K]

Answer:x=1012

Step-by-step explanation:

5 0
3 years ago
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Do yall know this ?<br><br><br><br><br><br><br><br><br><br> (2)
Flauer [41]
Nope we don’t know that
6 0
3 years ago
Ashley will tend a car for the weekend.she can choose one of two plans.the first plan has an initial fee of $49.96 and cost an a
Rom4ik [11]
First, you multiply $55.96 by $0.12 and you get $6.7152. Then, multiply $49.96 by $0.14 and you get $6.9944. If you subtract $69944-$6.7152 you get your answer which is $0.2792.
5 0
4 years ago
Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean
Zinaida [17]

Answer:

E[R] = 99 Ω

\sigma_R = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, E[R] = \frac{a+b}{2}  = \frac{95+103}{2} = \frac{198}{2} = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333

Hence,

The standard deviation of resistance, \sigma_R = \sqrt{V(R)} = \sqrt5.333 = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

z_1 = \frac{102-99}{2.3094} = 1.299

z_2 = \frac{98-99}{2.3094} = -0.433

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0
4 years ago
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