<span><span>√<span><span><span>(<span><span>3<span>x4</span></span><span>y3</span></span>)</span>2</span>⋅<span>(<span><span>6x</span>y</span>)</span></span></span><span><span><span><span>3<span>x4</span></span><span>y3</span></span>2</span>⋅<span><span>6x</span>y</span></span></span>Pull terms out from under the radical.<span><span><span>3<span>x4</span></span><span>y3</span></span><span>√<span><span>6x</span><span>y</span></span></span></span>
4.29 + 97.2 + 0.687 = 102.177
In adding decimal numbers, make sure that the decimal points are aligned. Since each number has different counts of numbers after the decimal point, use 0 to pad the missing places.
4.290
97.200
<u> 0.687
</u> 102.177
The count of numbers after the decimal point is the same count of number of the decimal who has the greatest count of number after the decimal point.
4.29 only has 2 counts of places after the decimal point
97.2 only has 1 count of place after the decimal point
0.687 has 3 counts of places after the decimal point.
The sum of the decimals must also have 3 counts of places after the decimal point.
Answer:
300 students are enrolled.
Step-by-step explanation:
As the university accepts 60% of the students who apply.
As 2000 students apply, it means that:
2000 × 60% ⇒ 2000 × 0.6 = 1200 students are accepted
Out of these 1200, 25% enrolled
1200 × 25% ⇒ 1200 × 0.25 = 300 students are enrolled
Therefore, 300 students are enrolled.
Y = -x + 4.....so sub in -x + 4 in for y in the other equation
x + 2y = -8
x + 2(-x + 4) = -8
x - 2x + 8 = -8
x - 2x = -8 - 8
-x = -16
x = 16
y = -x + 4
y = -16 + 4
y = - 12
one solution (16,-12)
