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Triss [41]
2 years ago
11

8. Find the measures of the three angles of a triangle if the sum of the measure of the first angle and three times

Mathematics
1 answer:
scoray [572]2 years ago
6 0

Answer:

C is the answer

Step-by-step explanation:

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Find the value of n in 2m-3n = 6 and 2m + 6n = 12.​
Nezavi [6.7K]

Answer:

n = 2/3

Step-by-step explanation:

2m - 3n = 6

– 2m + 6n = 12

<u>____-____-___</u>

-9n = -6

n = -6/-9

n = 2/3

Hence, the value of n in the given equations is 2/3.

4 0
2 years ago
Which angles are complementary to each other, will give brainliest
gayaneshka [121]

3 nd 4

Step-by-step explanation:

hope this helps

8 0
3 years ago
The function below is written in vertex form or intercept form. Rewrite them in standard form and show your work.
lora16 [44]

Answer:

The standard form as y=5x^2+30x+41

Step-by-step explanation:

Given: A function which is written in vertex form or intercept form.

We have to re-write it  in standard form that in terms of

Given y = 5(x+3)^2-4

Squaring  using (a+b)^2=a^2+b^2+2ab , we get,  

y=5(x^2+9+6x)-4

Multiply 5 inside , we get,

y=5x^2+45+30x-4

Solving further , we get,

y=5x^2+30x+41

Thus , we have obtained the standard form as y=5x^2+30x+41







8 0
3 years ago
Read 2 more answers
What is 625 over 6561 simplified?
erastovalidia [21]
<span> the answer is 0.09526. your welcome</span>
4 0
3 years ago
The quadratic function f(x) has a turning point at (-3,6). the quadratic y=2/3f(x)+3 would have a turning point of
NARA [144]

Answer:

C. (-3,11)

Step-by-step explanation:

Tp is (-3,6) implies the quadratic could have been

f(x) = (x+3)²+6

(2/3)f(x) = (2/3)[(x+3)²+6]

= (2/3)(x+3)²+4

(2/3)f(x)+3 = (2/3)(x+3)²+4+3

= (2/3)(x+3)²+7

Tp at (-3,7)

Alternately,

No change in domain so x remains-3

(2/3)f(x) changes y from 6 to 4 (6×2/3)

+3 increases the y by 3

i.e 4+3 = 7

So, (-3,7)

4 0
3 years ago
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