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Vladimir79 [104]
3 years ago
9

Which is the value of the rational expression 6-x/x+5 when x=2

Mathematics
1 answer:
Allisa [31]3 years ago
8 0

Answer:

4/7

Step-by-step explanation:

6-x/x+5 let us take x=2

6-2/2+5=4/7

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Solve x - 6x = 40 by factoring. What is<br> the solution?
marta [7]

Answer:

x=-8

Step-by-step explanation:

collect like terms

-5x=40

divide both sides of the equation by -5

so the answer would be x=-8

7 0
3 years ago
Enter the rate of change of the table below
poizon [28]
The rate of change is 23
4 0
2 years ago
A rectangular prism has a volume of 162 cubic centimeters. If the length, width, and height are reduced to 1/3 of their original
Colt1911 [192]
The original volume of the given prism is
l*w*h = 162
where l = length, w = width, h = height
Reducing 1/3 of each sides,
(1/3)l*(1/3)w*(1/3)h=(1/27)162
Thus,
The new volume is 162/27 = 6 cubic cm
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3 years ago
Ball drop with kinetic and potential energy
bagirrra123 [75]

Answer:

When the ball is dropped on the ground, the potential energy convert into kinetic energy. It had potential energy when it was held in the air waiting to be dropped, and It had kinetic energy when it was dropped because kinetic energy is when it's moving. when you drop it, your moving it.

Step-by-step explanation:

your welcome *bows*

7 0
2 years ago
Find the sum of the geometric series 512+256+ . . .+4
mario62 [17]

\bf 512~~,~~\stackrel{512\cdot \frac{1}{2}}{256}~~,~~...4

so, as you can see above, the common ratio r = 1/2, now, what term is +4 anyway?

\bf n^{th}\textit{ term of a geometric sequence}\\\\a_n=a_1\cdot r^{n-1}\qquad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\a_n=+4\end{cases}

\bf 4=512\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{4}{512}=\left( \cfrac{1}{2} \right)^{n-1}\\\\\\\cfrac{1}{128}=\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{1}{2^7}=\left( \cfrac{1}{2} \right)^{n-1}\implies 2^{-7}=\left( 2^{-1}\right)^{n-1}\\\\\\(2^{-1})^7=(2^{-1})^{n-1}\implies 7=n-1\implies \boxed{8=n}

so is the 8th term, then, let's find the Sum of the first 8 terms.

\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\n=8\end{cases}

\bf S_8=512\left[ \cfrac{1-\left( \frac{1}{2} \right)^8}{1-\frac{1}{2}} \right]\implies S_8=512\left(\cfrac{1-\frac{1}{256}}{\frac{1}{2}}  \right)\implies S_8=512\left(\cfrac{\frac{255}{256}}{\frac{1}{2}}  \right)\\\\\\S_8=512\cdot \cfrac{255}{128}\implies S_8=1020

7 0
3 years ago
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