Given, in the spinner 8 equal sectors, numbered 1 to 8.
So total numbers = 8.
Let, the probability of spinning a 3 is P(Three) and spinning an 8 is P(Eight).
Now we know that, probability of an event E is
P(E) = (number of outcomes in the event)/ (total number of possible outcomes).
So here number of outcomes for spinning a 3 is 1 and we have got total outcomes = 8.
So P(Three) = 
Similarly, P(Eight) = 
Probability of spinning a 3 or an 8 = P(Three) + P(Eight)
= 
As the denominator is same we can add the numerator.
= 
= 
Now we have to simplify the fraction by dividing the numerator and denominator by a common factor of them.
The common factor of 2 and 8 is 2. So by dividing them we will get,
= 
We have got the required answer.
The probability of spinning a 3 or an 8 is 
It’s 8/15 decimal form it’ll be 0.53 hope this helped !
I'm afraid your equation is not correctly set up. You need to identify the longest side of this right triangle; it is x. This is the "hypotenuse." Next, identify the lengths of the legs: they are sqrt(13) and 2sqrt(2).
Here's a refresher on the Pythagorean Theorem:
(hypotenuse)^2 = (leg 1)^2 + (leg 2)^2
Applying this Theorem here, [x]^2 = [2sqrt(2)]^2 + [sqrt(13)\^2
Solve this for x^2, and then take the positive root (only) of your result.
Add 8 on both sides in order to isolate n:
-3 + 8 < n - 8 + 8
5 < n
Sec θ = 3
1/cos θ = 3
cos θ = 1/3
csc (90 - θ) = 1/sin (90 - θ) = 1/cos θ = 1/(1/3) = 3
Therefore, csc (90 - θ) = 3.