Answer:
The correct Answer is 0.0571
Explanation:
53% of U.S. households have a PCs.
So, P(Having personal computer) = p = 0.53
Sample size(n) = 250
np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10
So, we can just estimate binomial distribution to normal distribution
Mean of proportion(p) = 0.53
Standard error of proportion(SE) = 
= 
= 0.0316
For x = 120, sample proportion(p) = 
= 
= 0.48
So, likelihood that fewer than 120 have a PC
= P(x < 120)
= P( p^ < 0.48 )
= P(z < 
) (z=
)
= P(z < -1.58)
= 0.0571 ( From normal table )
no longer returns an error but your math seems to have something wrong with it, always returns 0
Console.WriteLine("Enter a percentage here");
int Percent = int.Parse(Console.ReadLine());
Console.WriteLine("Enter your number here");
int Number = int.Parse(Console.ReadLine());
int result = Percent / 100 * Number;
In excel spreadsheets, you need to consider specifying relationships between the information you have
stored in your spreadsheets when creating formulas. The elements that will help
you understand using spreadsheet are the constants, operators, references and
functions. This will enable you to use the formulas, without hassle in
spreadsheets.
Inertia would keep them going the same speed as the car was going. therefore, the person not wearing a seatbelt would be sent flying forward, probably ending up dead
