<span>1. E
2. B
3. D
4. F
5. C
6. A
Let's go about solving this problem in a process of elimination. So I'll be making each match in the easiest (for me) order.
Initially I'm not sure about 1 & 2. But the match for #3 is rather obvious. So
3. Blending non-related clips and images to make a new video.
This is a "D. Mashup"
The next obvious answer is for #6. That is
6. Everything that happens to the video and audio after the footage has been shot.
This is "A. Post production"
Now of the remaining 4 choices, "Final Cut Pro" sounds like an actual program. And there's only 1 option that's asking for a specific program. So we have
2. Most popular post-production editing package by Apple
Answer "B. Final Cut Pro"
This leaves us with 3 options "C. Non-linear editing", "E. AVID", and "F. Timeline"
Of these 3, only "F. Timeline" sounds list an element in the interface of a video editing package. So we have
4. An element in the interface of editing software
Answer "F. Timeline"
Now a quick google search reveals that "AVID" is a software company that makes video editing software. So
1. Company that makes high-end post-production software.
Answer "E. AVID"
And we're left with
5. Transferring film onto Beta, digitizing it to the computer, and editing it
Answer "C. Non-linear editing"
Now the only questionable choice is Non-linear editing (NLE) for #5. So doing a quick google search and I see that #5 over specified the task. The key characteristic of NLE is having the video and audio in digital form that can be readily accessed via a computer. And #5 does qualify for that task. So here's the final answers
1. E
2. B
3. D
4. F
5. C
6. A</span>
JQuery is the final element of a e-mail message I believe
Answer:
- import java.util.Scanner;
- public class Main {
-
- public static void main(String[] args) {
-
- Scanner input = new Scanner(System.in);
- System.out.print("Please enter two characters: ");
- String inputStr = input.nextLine();
-
- if(inputStr.charAt(0) == 'B' || inputStr.charAt(0) == 'b'){
- System.out.println("Biology");
- }
- else if(inputStr.charAt(0) == 'C' || inputStr.charAt(0)== 'c'){
- System.out.println("Computer Science");
- }
- else if(inputStr.charAt(0) == 'I' || inputStr.charAt(0) == 'i')
- {
- System.out.println("Information Technology and Systems");
- }
- else{
- System.out.println("Invalid major");
- }
-
- int num = Character.getNumericValue(inputStr.charAt(1));
-
- if(num >= 1 && num <= 4){
- switch (num){
- case 1:
- System.out.println("freshman");
- break;
- case 2:
- System.out.println("sophomore");
- break;
- case 3:
- System.out.println("junior");
- break;
- case 4:
- System.out.println("senior");
- break;
- }
-
- }
- else{
- System.out.println("Invalid year status");
- }
-
- }
-
- }
Explanation:
The code consists of two main parts. The part 1 is to validate the input major and print out the major according to the input character (Line 10 -22). If the input character is not matched with the target letters, a message invalid major will be displayed.
The part 2 is to validate the year status to make sure it only fall within the range of 1-4 (Line 26 -45). If within the range, the program will display the year major accordingly. If not a message invalid year status will be displayed.
def pig_latin(word):
if word[0].lower() in 'aeiou':
word = word + 'way'
else:
t=''
for x in range(len(word)):
if word[x].lower() in 'aeiou':
break
if word[x].lower() == 'y' and x>0:
break
else:
t+=word[x].lower()
if word[0].isupper():
word = word[len(t):]+word[:len(t)].lower()+'ay'
word = word.title()
else:
word = word[len(t):]+word[:len(t)].lower()+'ay'
return word
word = 'test'
pl = pig_latin(word)
print(pl)
I wrote my code in python 3.8. I hope this helps.
