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Nina [5.8K]
3 years ago
5

Determine the center and radius of the following circle equation: x2 + y2 – 10x + 8y + 40 = 0

Mathematics
2 answers:
antiseptic1488 [7]3 years ago
6 0

Answer:

The center of this circle is (5, -4) and the radius is 1.

Step-by-step explanation:

First regroup these terms according to x and y :

x^2 - 10x + y^2 + 8y = -40

Next, complete the square for x^2 - 10x:  x^2 - 10x + 5^2 - 5^2.

and the same for y^2 + 8y:  y^2 + 8y + 16 - 16

Substituting these results into x^2 - 10x + y^2 + 8y = -40, we get:

x^2 - 10x + 5^2 - 5^2 y^2 + 8y + 16 - 16 = -40.

Next, rewrite x^2 - 10x + 25 and y^2 + 8y + 16 as squares of binomials:

Then x^2 - 10x + 5^2 - 5^2 y^2 + 8y + 16 - 16 = -40 becomes:

(x - 5)^2 + (y + 4)^2 - 25 - 16 = -40, or:

(x - 5)^2 + (y + 4)^2 = 1

This equation has the form (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius.  Matching like terms, we get h = 5, k = -4 and r = 1.

The center of this circle is (5, -4) and the radius is 1.

RoseWind [281]3 years ago
4 0

Answer:

Center (5,-4) Radius = 1

Step-by-step explanation:

Put it in the form of the standard circle equation after dividing everything by 2. (-10x/2=-5x) (8y/2=4y) Since the radius wasn't given, it's just going to be a 1.

(x-5)^2+y(-(-4))^2 = 1^2

Hence, center (5, -4) and radius 1.

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Answer:

The sum of an even number plus an odd number is odd.

Step-by-step explanation:

The sum of an even number and an odd number is odd.

For example:

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The end digit of an even number is always 0, 2, 4, 6, or 8

The end digit of an odd number is 1, 3, 5, 7, or 9.

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3 years ago
The length of a rectangle is 2 cm more than four times the width. If the perimeter of the rectangle is 84 cm, what are its dimen
katovenus [111]

Answer:

Length 34 cm

Width 8 cm

Step-by-step explanation:

Let

x-----> the length of the rectangle

y----> the width of the rectangle

we know that

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so

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42=x+y ----> equation A

x=4y+2 -----> equation B

substitute equation B in equation A and solve for y

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The dimensions are

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25<=x

i need 20 characters to answer

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